E° for Cl2/Cl- = +1.36, I2/ I- = +0.53, Ag+/Ag = +0.79, Na+/ Na = -2.71 and Li+/ Li = -3.04 V. What is the order of decreasing reducing strength for these species?

Question

E° for Cl2/Cl- = +1.36, I2/ I- = +0.53, Ag+/Ag = +0.79, Na+/ Na = -2.71 and Li+/ Li = -3.04 V. What is the order of decreasing reducing strength for these species? (A) Li > Cl- >Ag > I- >Na (B) Li > Na >I- > Ag >Cl- (C) Cl- > Ag > I- > Na > Li (D) Na > Li > Ag >Cl- > I-

Tardigrade Admin · Accepted Answer

The order is Li > Na > I- > Ag > Cl -

Q. $E^{\circ}$ for $C l_{2} / C l^{-} = + 1.36$ , $I_{2} / I^{-} = + 0.53$ , $A g^{+} / A g = + 0.79$ , $N a^{+} / N a = - 2.71$ and $L i^{+} / L i = - 3.04 V$ . What is the order of decreasing reducing strength for these species?

$L i > C l^{-} > A g > I^{-} > N a$

$L i > N a > I^{-} > A g > C l^{-}$

$C l^{-} > A g > I^{-} > N a > L i$

$N a > L i > A g > C l^{-} > I^{-}$

The order is $L i > N a > I^{-} > A g > C l^{-}$

Q. E∘ for Cl2​/Cl−=+1.36, I2​/I−=+0.53, Ag+/Ag=+0.79, Na+/Na=−2.71 and Li+/Li=−3.04V. What is the order of decreasing reducing strength for these species?

Li>Cl−>Ag>I−>Na

Li>Na>I−>Ag>Cl−

Cl−>Ag>I−>Na>Li

Na>Li>Ag>Cl−>I−