E text cell of the following cell is P t(s) mid H2(g), bar | H +( l M ) | H +(0.1 M )| H 2(g), 1 bar mid Pt (s)

Question

E text cell of the following cell is P t(s) mid H2(g), bar | H +( l M ) | H +(0.1 M )| H 2(g), 1 bar mid Pt (s) (A) (-2.303 RT/F) (B) (2.303 RT/F) (C) (-2.303 RT/2F) (D) (2.303 RT/2F)

Tardigrade Admin · Accepted Answer

(a) operatornamePt(s) mid H 2(g), 1 bar | H +(1 M ) | H +(0.1 M )| H 2(g), 1 bar mid operatornamePt(s) Half cell corresponding to the reaction are At cathode, H +(a q)+e- longrightarrow (1/2) H2 At anode, (1/2) H2 longrightarrow H +(a q)+e- Nernst equation, E text cell =E text cell °-(2303 R T/n F) log [(1/ H +)] E text cell =0-(2303 R T/F) log [(1/0.1)] =-(2303 R T/F) log 10 E text cell =-(2303 R T/F)

Q. $E_{cell}$ of the following cell is $Pt (s) ∣ H_{2} (g)$ , bar $∣ H^{+} (lM) ∥ H^{+} (0.1 M) ∣ H_{2} (g), 1$ bar $∣ Pt (s)$

$\frac{- 2.303 RT}{F}$

$\frac{2.303 RT}{F}$

$\frac{- 2.303 RT}{2 F}$

$\frac{2.303 RT}{2 F}$

$\frac{RT}{2 F}$

Q. Ecell ​ of the following cell is Pt(s)∣H2​(g), bar ∣H+(lM)∥H+(0.1M)∣H2​(g),1 bar ∣Pt(s)

F−2.303RT​

F2.303RT​

2F−2.303RT​

2F2.303RT​