During the head on collision of two masses of 1 kg and 2 kg , the maximum energy of deformation is (100/3) J . If before collision the masses are moving in the opposite direction, then their velocity of approach before the collision is

Question

During the head on collision of two masses of 1 kg and 2 kg , the maximum energy of deformation is (100/3) J . If before collision the masses are moving in the opposite direction, then their velocity of approach before the collision is (A) 10 m/s (B) 5 m/s (C) 20 m/s (D) 10√2 m/s

Tardigrade Admin · Accepted Answer

By Reduced mass concept Δ E=(1/2)μ vr2 Δ E= Maximum energy of deformation μ = Reduced mass vr= Velocity of approach also, μ =(m1 m2/m1 + m2) on substituting values from question (100/3)=(1/2)× (1 × 2/1 + 2)× vr2 ⇒ vr=√100 vr=10m/s

Q. During the head on collision of two masses of $1$ $k g$ and $2$ $k g$ , the maximum energy of deformation is $\frac{100}{3}$ $J$ . If before collision the masses are moving in the opposite direction, then their velocity of approach before the collision is

$10$ $m / s$

$5$ $m / s$

$20$ $m / s$

$102$ $m / s$

Q. During the head on collision of two masses of 1 kg and 2 kg , the maximum energy of deformation is 3100​ J . If before collision the masses are moving in the opposite direction, then their velocity of approach before the collision is

10 m/s

5 m/s

20 m/s

102​ m/s

By Reduced mass concept ΔE=21​μvr2​ ΔE= Maximum energy of deformation μ= Reduced mass vr​= Velocity of approach also, μ=m1​+m2​m1​m2​​ on substituting values from question 3100​=21​×1+21×2​×vr2​ ⇒vr​=100​ vr​=10m/s

Q. During the head on collision of two masses of $1$ $k g$ and $2$ $k g$ , the maximum energy of deformation is $\frac{100}{3}$ $J$ . If before collision the masses are moving in the opposite direction, then their velocity of approach before the collision is

$10$ $m / s$

$5$ $m / s$

$20$ $m / s$

$102$ $m / s$