During the conversion of NH 2 OH arrow N 2 O, the equivalent weight of NH 2 OH (mol. wt. of NH 2 OH is M ) is

Question

During the conversion of NH 2 OH arrow N 2 O, the equivalent weight of NH 2 OH (mol. wt. of NH 2 OH is M ) is (A) M (B) M/2 (C) M/4 (D) M/5

Tardigrade Admin · Accepted Answer

overset-1NH 2 OH longrightarrow overset+1N 2 O Conversion factor, n =+1-(-1) =+2 Equivalent wt. of NH 2 OH =( text molecular weight / text conversion factor ) =(M/2)

Q. During the conversion of $N H_{2} O H \to N_{2} O$ , the equivalent weight of $N H_{2} O H$ (mol. wt. of $N H_{2} O H$ is $M$ ) is

M

M/2

M/4

M/5

$N H_{2} - 1 O H ⟶ N_{2} + 1 O$
Conversion factor, $n = + 1 - (- 1)$
$= + 2$
Equivalent wt. of $N H_{2} O H$
$= \frac{molecular weight}{conversion factor}$
$= \frac{M}{2}$

Q. During the conversion of NH2​OH→N2​O, the equivalent weight of NH2​OH (mol. wt. of NH2​OH is M ) is

M

M/2

M/4

M/5

NH2​−1​OH⟶N2​+1​O Conversion factor, n=+1−(−1) =+2 Equivalent wt. of NH2​OH = conversion factor molecular weight ​ =2M​

Q. During the conversion of $N H_{2} O H \to N_{2} O$ , the equivalent weight of $N H_{2} O H$ (mol. wt. of $N H_{2} O H$ is $M$ ) is

$N H_{2} - 1 O H ⟶ N_{2} + 1 O$
Conversion factor, $n = + 1 - (- 1)$
$= + 2$
Equivalent wt. of $N H_{2} O H$
$= \frac{molecular weight}{conversion factor}$
$= \frac{M}{2}$