During the charging of lead storage battery, the reaction at anode is represented by

Question

During the charging of lead storage battery, the reaction at anode is represented by (A) Pb 2++ SO 42- longrightarrow PbSO 4 (B) PbSO 4+ H 2 O longrightarrow PbO 2+ SO 42-+2 H + (C) Pb longrightarrow Pb 2++2 e- (D) Pb 2++2 e- longrightarrow Pb

Tardigrade Admin · Accepted Answer

The following reactions take place during the charging: At Anode: PbSO 4(s)+2 e- arrow Pb (s)+ SO 4(a q)2- At Cathode: PbSO 4(s)+2 H 2 O (l) arrow PbO 2(s)+ SO 4(a q)2-+4 H ++2 e-

Q. During the charging of lead storage battery, the reaction at anode is represented by

$P b^{2 +} + S O_{4}^{2 -} ⟶ P b S O_{4}$

$P b S O_{4} + H_{2} O ⟶ P b O_{2} + S O_{4}^{2 -} + 2 H^{+}$

$P b ⟶ P b^{2 +} + 2 e^{-}$

$P b^{2 +} + 2 e^{-} ⟶ P b$

The following reactions take place during the charging :

At Anode $: P b S O_{4 (s)} + 2 e^{-} \to P b_{(s)} + S O_{4 (a q)}^{2 -}$

At Cathode $: P b S O_{4 (s)} + 2 H_{2} O_{(l)} \to P b O_{2 (s)} + S O_{4 (a q)}^{2 -} + 4 H^{+} + 2 e^{-}$

Q. During the charging of lead storage battery, the reaction at anode is represented by

Pb2++SO42−​⟶PbSO4​

PbSO4​+H2​O⟶PbO2​+SO42−​+2H+

Pb⟶Pb2++2e−

Pb2++2e−⟶Pb

The following reactions take place during the charging : At Anode :PbSO4(s)​+2e−→Pb(s)​+SO4(aq)2−​ At Cathode :PbSO4(s)​+2H2​O(l)​→PbO2(s)​+SO4(aq)2−​+4H++2e−

$P b^{2 +} + S O_{4}^{2 -} ⟶ P b S O_{4}$

$P b S O_{4} + H_{2} O ⟶ P b O_{2} + S O_{4}^{2 -} + 2 H^{+}$

$P b ⟶ P b^{2 +} + 2 e^{-}$

$P b^{2 +} + 2 e^{-} ⟶ P b$

The following reactions take place during the charging :

At Anode $: P b S O_{4 (s)} + 2 e^{-} \to P b_{(s)} + S O_{4 (a q)}^{2 -}$

At Cathode $: P b S O_{4 (s)} + 2 H_{2} O_{(l)} \to P b O_{2 (s)} + S O_{4 (a q)}^{2 -} + 4 H^{+} + 2 e^{-}$