During reduction of aldehydes with hydrazine and potassium hydroxide, the first is the formation of

Question

During reduction of aldehydes with hydrazine and potassium hydroxide, the first is the formation of (A) R - CH = N - NH 2 (B) R-C ≡ N (C)  (D) R - CH = NH

Tardigrade Admin · Accepted Answer

Correct answer is (a) R - CH = N - NH 2

Q. During reduction of aldehydes with hydrazine and potassium hydroxide, the first is the formation of

$R - C H = N - N H_{2}$

$R - C \equiv N$

$R - C H = N H$

Correct answer is (a) $R - C H = N - N H_{2}$

Q. During reduction of aldehydes with hydrazine and potassium hydroxide, the first is the formation of

R−CH=N−NH2​

R−C≡N

R−CH=NH

Correct answer is (a) R−CH=N−NH2​

$R - C H = N - N H_{2}$

$R - C \equiv N$

$R - C H = N H$

Correct answer is (a) $R - C H = N - N H_{2}$