Question

During nitration of benzene, the attacking electrophile is

• A. $N{O}_3^{-}$
• B. $N{O}_2^{-}$
• C. $N{O}_2^{+}$
• D. $HN{O}_3$

Answer 1

Answer: (C)

During nitration of benzene, the attacking electrophile is $N{O}_2^{+}$.
It is formed by the reaction between $HN{O}_3$ and $H_{2}S{O}_4$ as shown below :