Question

During motion of a man from equator to pole of earth, its weight will (neglect the effect of change in the radius of earth)

• A. Increase by 0.34%
• B. Decrease by 0.34%
• C. Increase by 0.52%
• D. Decrease by 0.52%

Answer 1

Answer: (A)

$w_{eq}=mg-m{\omega }^2{R}_e$
$w_p=mg$
$\frac{w_p-w_{eq}}{w_{\theta q}}=\frac{m{\omega }^{2}R}{mg-m{\omega }^{2}R}$
$=\frac{{\omega }^{2}R}{g-{\omega }^{2}R}$
$\left[{\omega }^{2}R=0.0337m/s^2\right]$
$\Rightarrow \frac{\Delta w}{w_{eq}}=\frac{0.0337}{9.81-0.0337}=0.3447\times 10^{-2}$
$\Rightarrow \frac{\Delta w}{w_{eq}}\times 100=0.3447$
$\Rightarrow$ Increases by $0.34\%$