Question

During estimation of oxalic acid vs $KMn{O}_4$ , self indicator is :

• A. $KMn{O}_4$
• B. Oxalic acid
• C. $K_{2}S{O}_4$
• D. $MnS{O}_4$

Answer 1

Answer: (A)

$KMn{O}_4$ work as self indicator when this reaction takes place the oxalic acid is converted into carbon dioxide and permanganate ion is converted into $M{n}^{+2}$ ion which is of very light pink color and indicates that reaction is completed $\underset{purple/pink}{2KMn{O}_4}+5H_2{C}_2{O}_4+3H_{2}S{O}_4\to \underset{colorless}{2MnS{O}_4}+10C{O}_2+8H_{2}O+K_{2}S{O}_4$