Q. During estimation of oxalic acid vs $KMnO_{4}$ , self indicator is :
NTA AbhyasNTA Abhyas 2022
Solution:
Solution:
$KMnO_{4}$ work as self indicator when this reaction takes place the oxalic acid is converted into carbon dioxide and permanganate ion is converted into $Mn^{+ 2}$ ion which is of very light pink color and indicates that reaction is completed $\underset{purple / pink}{2 KMnO_{4}}+5H_{2}C_{2}O_{4}+3H_{2}SO_{4} \rightarrow \underset{color less}{2 MnSO_{4}}+10CO_{2}+8H_{2}O+K_{2}SO_{4}$