Question

During a projectile motion, if the maximum height equals to the horizontal range, then the angle of projection with the horizontal is :-

• A. $ta{n}^{-1}\left(1\right)$
• B. $ta{n}^{-1}\left(2\right)$
• C. $ta{n}^{-1}\left(3\right)$
• D. $ta{n}^{-1}\left(4\right)$

Answer 1

Answer: (D)

$H=\frac{u^{2}si{n}^2\theta }{2g}$ and $R=\frac{u^{2}sin2\theta }{g}$
since, $H=R$
$\frac{u^{2}si{n}^2\theta }{2g}=\frac{u^2\times 2sin\theta cos\theta }{g}$
or $tan\theta =4$ or $\theta =ta{n}^{-1}\left(4\right)$