Distance between tetrahedral and octahedral void in fcc lattice will be (Given edge length of unit cell = a)

Question

Distance between tetrahedral and octahedral void in fcc lattice will be (Given edge length of unit cell = a) (A) (√3 a/4) (B) √3a (C) √3(a/2) (D) (√3 a/3)

Tardigrade Admin · Accepted Answer

Octahedral void is found at centre of cube and edge centre while tetrahedral voids are present at 1/4th of the distance along each body diagonal.

2 \times

distance between tetrahedral and octahedral voids

= \frac{3 a}{2}

So distance between tetrahedral and octahedral void

= \frac{3 a}{4}

.

Q. Distance between tetrahedral and octahedral void in fcc lattice will be

(Given edge length of unit cell = a)

$\frac{3 a}{4}$

$3 a$

$3 \frac{a}{2}$

$\frac{3 a}{3}$

Octahedral void is found at centre of cube and edge centre while tetrahedral voids are present at 1/4th of the distance along each body diagonal.

$2 \times$ distance between tetrahedral and octahedral voids $= \frac{3 a}{2}$

So distance between tetrahedral and octahedral void $= \frac{3 a}{4}$ .

Q. Distance between tetrahedral and octahedral void in fcc lattice will be (Given edge length of unit cell = a)

43​a​

3​a

3​2a​

33​a​