Question

Distance between successive compression and rarefaction is $1m$ and velocity of sound is $360m{s}^{-1}$. Find frequency :

• A. 180 Hz
• B. 45 Hz
• C. 120 Hz
• D. 90 Hz

Answer 1

Answer: (A)

$\lambda =2d=2m$
$v=\frac{\nu }{\lambda }=\frac{360m{s}^{-1}}{2m}=180Hz$
Reason : As it can be understood from the figure, distance between successive compressions and rarefactions is one half of the wavelength.