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  4. Distance between successive compression and rarefaction is 1 m and velocity of sound is 360 ms-1. Find frequency :

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Q. Distance between successive compression and rarefaction is $1 \,m$ and velocity of sound is $360 \,ms^{-1}$. Find frequency :

Rajasthan PMTRajasthan PMT 2006Electromagnetic Waves

Solution:

$\lambda=2 d=2 m $
$v=\frac{\nu}{\lambda}=\frac{360 \,ms ^{-1}}{2 \,m }=180 \,Hz$
Reason : As it can be understood from the figure, distance between successive compressions and rarefactions is one half of the wavelength.