Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is :

Question

Dissolving 120 g of a compound of (mol. wt. 60) in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is : (A) 1.00 M (B) 2.00 M (C) 2.50 M (D) 4.00 M

Tardigrade Admin · Accepted Answer

Molarity of solution =(((120/60))/(1120)1.12×(1)100 = 2 M

Q. Dissolving $120 g$ of a compound of (mol. wt. $60$ ) in $1000 g$ of water gave a solution of density $1.12 g / m L$ . The molarity of the solution is :

1.00 M

2.00 M

2.50 M

4.00 M

Molarity of solution = $\frac{( \frac{120}{60} )}{\frac{1120}{1.12} \times \frac{1}{100}}$

$= 2 M$

Q. Dissolving 120g of a compound of (mol. wt. 60) in 1000g of water gave a solution of density 1.12g/mL. The molarity of the solution is :