See the graph of y=x and sinx in the following figure
From the graph, when x→0+, the graph of y=x is above the graph of y=sinx, i.e., sinx˙<x⇒xsinx<1 ⇒x→0+lim[xsinx]=0
When x→0−, the graph of y=x is below the graph of y=sinx, i.e., sinx>x⇒xsinx<1 (As x is negative)
or x→0−lim[xsinx]=0
Thus, x→0lim[xsinx]=0