Question

$\underset{\theta \to 0}{\lim }\frac{\sin m^2\theta }{\theta }$ is equal to :

• A. 0
• B. 1
• C. m
• D. $m^2$

Answer 1

Answer: (D)

Consider $\underset{\theta \to 0}{\lim }\frac{\sin m^2\theta }{\theta }$
= $\underset{\theta \to 0}{\lim }\left(\frac{\sin m^2\theta }{m^2\theta }\right)m^2=1\times m^2=m^2$