Question

$\underset{n\to \infty }{\lim }\frac{-3n+(-1{)}^n}{4n-(-1{)}^n}$ is equal to

• A. $-\frac{3}{4}$
• B. 0 if $n$ is even
• C. $-\frac{3}{4}$ if $n$ is odd
• D. None of these

Answer 1

Answer: (A), (C)

$\underset{n\to \infty }{\lim }\frac{-3+\frac{(-1{)}^n}{n}}{4+\frac{(-1{)}^n}{n}}=\frac{-3}{4}$