Direction of the first secondary maximum in the Fraunhoffer diffraction pattern at a single slit is given by (a is the width of the slit):

Question

Direction of the first secondary maximum in the Fraunhoffer diffraction pattern at a single slit is given by (a is the width of the slit): (A) a sin θ=(λ/2) (B) a cos θ=(3 λ/2) (C) a sin θ=λ (D) a sin θ=(3 λ/2)

Tardigrade Admin · Accepted Answer

Relation for the maximum ((2 n+1) λ/2)=a sin θ ((2 × 1+1) λ/2)=a sin θ[n=1] (3 λ/2)=a sin θ

Q. Direction of the first secondary maximum in the Fraunhoffer diffraction pattern at a single slit is given by (a is the width of the slit):

$a sin θ = \frac{λ}{2}$

$a cos θ = \frac{3 λ}{2}$

$a sin θ = λ$

$a sin θ = \frac{3 λ}{2}$

Relation for the maximum
$\frac{( 2 n + 1 ) λ}{2} = a sin θ$
$\frac{( 2 \times 1 + 1 ) λ}{2} = a sin θ [n = 1]$
$\frac{3 λ}{2} = a sin θ$

Q. Direction of the first secondary maximum in the Fraunhoffer diffraction pattern at a single slit is given by (a is the width of the slit):

asinθ=2λ​

acosθ=23λ​

asinθ=λ

asinθ=23λ​

Relation for the maximum 2(2n+1)λ​=asinθ 2(2×1+1)λ​=asinθ[n=1] 23λ​=asinθ

$a sin θ = \frac{λ}{2}$

$a cos θ = \frac{3 λ}{2}$

$a sin θ = λ$

$a sin θ = \frac{3 λ}{2}$

Relation for the maximum
$\frac{( 2 n + 1 ) λ}{2} = a sin θ$
$\frac{( 2 \times 1 + 1 ) λ}{2} = a sin θ [n = 1]$
$\frac{3 λ}{2} = a sin θ$