Question

Dipole moment of $HCl=1.03D,HI=0.38D$. Bond length of $HCl=1.3\mathring{A}$ and $HI=1.6\mathring{A}$. The ratio of fraction of electric charge, $\delta$, existing on each atom in $HCl$ and $HI$ is

• A. 12 : 1
• B. 2.7 : 1
• C. 3.3 : 1
• D. 1 : 3.3

Answer 1

Answer: (C)

From the definition of dipole moment,

$\mu =\delta \times d$

where, $\delta =$ magnitude of electric charge

$d=$ distance between particles (here bond length)

$\therefore \delta =\frac{\mu }{d}$

or, $\frac{{\delta }_{HCl}}{{\delta }_{HI}}=\frac{{\mu }_{HCl}}{d_{HCl}}\times \frac{d_{HI}}{{\mu }_{HI}}$

$=\frac{1.03\times 1.6}{1.3\times 0.38}=3.3:1$