Dipole-dipole interaction energy between polar molecules in solids depends on the radius of the molecule (r) and it is directly proportional to

Question

Dipole-dipole interaction energy between polar molecules in solids depends on the radius of the molecule (r) and it is directly proportional to (A) ((1/r2)) (B) ((1/r6)) (C) ((1/r)) (D) ((1/r5))

Tardigrade Admin · Accepted Answer

Dipole-dipole interaction energy between polar molecules in solids depends on the distance between them as per following relation:

Dipole-dipole interaction energy

\propto \frac{1}{r ^{3}}

(r =

radius of the molecule under consideration)

Q. Dipole-dipole interaction energy between polar molecules in solids depends on the radius of the molecule $(r)$ and it is directly proportional to

$(\frac{1}{r ^{2}})$

$(\frac{1}{r ^{6}})$

$(\frac{1}{r})$

$(\frac{1}{r ^{5}})$

$(\frac{1}{r ^{3}})$

Dipole-dipole interaction energy between polar molecules in solids depends on the distance between them as per following relation:

Dipole-dipole interaction energy $\propto \frac{1}{r ^{3}}$

$(r =$ radius of the molecule under consideration)

Q. Dipole-dipole interaction energy between polar molecules in solids depends on the radius of the molecule (r) and it is directly proportional to

(r21​)

(r61​)

(r1​)

(r51​)

(r31​)

Dipole-dipole interaction energy between polar molecules in solids depends on the distance between them as per following relation: Dipole-dipole interaction energy ∝r31​ (r= radius of the molecule under consideration)