Question

Dimensions of universal gravitational constant will be

• A. $[M{L}^3{T}^{-2}]$
• B. $[M{L}^{-1}{L}^3{T}^{-2}]$
• C. $[M^{-1}{L}^2{T}^2]$
• D. None of these

Answer 1

Answer: (B)

$<br/>G=\frac{F_r^2}{m_1{m}_2}<br/>$
Dimensions of $G=\frac{\left[ML{T}^{-2}\right]\left[L^2\right]}{\left[M^2\right]}=\left[M^{-1}{L}^3{T}^{-2}\right]$