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  4. Dimensions of universal gravitational constant will be

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Q. Dimensions of universal gravitational constant will be

Rajasthan PETRajasthan PET 2001

Solution:

$
G=\frac{F_{r}^{2}}{m_{1} m_{2}}
$
Dimensions of $G=\frac{\left[ MLT ^{-2}\right]\left[ L ^{2}\right]}{\left[ M ^{2}\right]}=\left[ M ^{-1} L ^{3} T ^{-2}\right]$