Question

Dimensional formula for thermal conductivity is (here $K$ denotes the temperature)

• A. $ML{T}^{-3}K$
• B. $ML{T}^{-2}K$
• C. $ML{T}^{-2}{K}^{-2}$
• D. $ML{T}^{-3}{K}^{-1}$

Answer 1

Answer: (D)

$\because \frac{d\theta }{dt}=kA\frac{dT}{dx}$
$k=\frac{\left(\frac{d\theta }{dt}\right)}{A\left(\frac{dT}{dx}\right)}$
$[k]=\frac{\left[M{L}^2{T}^{-3}\right]}{\left[L^2\right]\left[K{L}^{-1}\right]}$
$=\lfloor ML{T}^{-3}{K}^{-1}\rfloor$