Diborane is a Lewis acid forming addition compound B2H6.2NH3 with NH3, a Lewis base. This

Question

Diborane is a Lewis acid forming addition compound B2H6.2NH3 with NH3, a Lewis base. This (A) Is ionic and exists as[BH2(NH3)2]+ and [BH4] ions (B) On heating, is converted into borazine, B3N3H6 (called inorganic benzene) (C) Both(a) and (b) are correct (D) Neither (a) nor (b) is correct

Tardigrade Admin · Accepted Answer

At low temperature, an addition product. B2 H6 ⋅ 2 N H3 exists as [B H2(N H3)2]- ions 3 B2 H6 ⋅ 2 N H3 xrightarrow200° C underset textBorazole2 B3 N3 H6+12 H2 uparrow <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/1ee9275ae7e9376333d1b913a2de1401-.jpeg" />

Q. Diborane is a Lewis acid forming addition compound $B_{2} H_{6} .2 N H_{3}$ with $N H_{3}$ , a Lewis base. This

Is ionic and exists as $[B H_{2} (N H_{3})_{2}]^{+}$ and $[B H_{4}]$ ions

On heating, is converted into borazine, $B_{3} N_{3} H_{6}$ (called inorganic benzene)

Both(a) and (b) are correct

Neither (a) nor (b) is correct

At low temperature, an addition product.
$B_{2} H_{6} \cdot 2 N H_{3}$ exists as $[B H_{2} (N H_{3})_{2}]^{-}$ ions
$3 B_{2} H_{6} \cdot 2 N H_{3} 20 0^{\circ} C Borazole 2 B_{3} N_{3} H_{6} + 12 H_{2} ↑$

Q. Diborane is a Lewis acid forming addition compound B2​H6​.2NH3​ with NH3​, a Lewis base. This

Is ionic and exists as[BH2​(NH3​)2​]+ and [BH4​] ions

On heating, is converted into borazine, B3​N3​H6​ (called inorganic benzene)