Question

Diborane is a Lewis acid forming addition compound $B_{2}H_{6}.2NH_{3}$ with $NH_{3}$, a Lewis base. This

• A. Is ionic and exists as$[BH_{2}(NH_{3})_{2}]^{+}$ and $[BH_{4}]$ ions
• B. On heating, is converted into borazine, $B_{3}N_{3}H_{6}$ (called inorganic benzene)
• C. Both(a) and (b) are correct
• D. Neither (a) nor (b) is correct

Answer 1

Answer: (C)

At low temperature, an addition product.
$B_{2} H_{6} \cdot 2 N H_{3}$ exists as $\left[B H_{2}\left(N H_{3}\right)_{2}\right]^{-}$ ions
$3 B_{2} H_{6} \cdot 2 N H_{3} \xrightarrow{200^{\circ} C} \underset{\text{Borazole}}{2 B_{3} N_{3} H_{6}}+12 H_{2} \uparrow$