Diazonium salt is obtained when aniline reacts with

Question

Diazonium salt is obtained when aniline reacts with (A) cold NaOH (B)  NaNO2 and HCl (0-5°C)  (C)  SnCl2 at 10°C  (D)  N2O at (0-5°C)

Tardigrade Admin · Accepted Answer

Diazodsadon: Benzene diazonium chloride is prepared by treating aniline with sodium nitrite and hydrochloric acid at 0°C-5°C . This reaction is called diazotisation. NaNO2+HClarrow NaCl+HNO2

Q. Diazonium salt is obtained when aniline reacts with

cold NaOH

$N a N O_{2}$ and $H Cl (0 - 5^{\circ} C)$

$S n C l_{2}$ at $1 0^{\circ} C$

$N_{2} O$ at $(0 - 5^{\circ} C)$

Diazodsadon : Benzene diazonium chloride is prepared by treating aniline with sodium nitrite and hydrochloric acid at $0^{\circ} C - 5^{\circ} C$ . This reaction is called diazotisation.
$N a N O_{2} + H Cl \to N a Cl + H N O_{2}$

Q. Diazonium salt is obtained when aniline reacts with

cold NaOH

NaNO2​ and HCl(0−5∘C)

SnCl2​ at 10∘C

N2​O at (0−5∘C)

Diazodsadon : Benzene diazonium chloride is prepared by treating aniline with sodium nitrite and hydrochloric acid at 0∘C−5∘C . This reaction is called diazotisation. NaNO2​+HCl→NaCl+HNO2​

$N a N O_{2}$ and $H Cl (0 - 5^{\circ} C)$

$S n C l_{2}$ at $1 0^{\circ} C$

$N_{2} O$ at $(0 - 5^{\circ} C)$

Diazodsadon : Benzene diazonium chloride is prepared by treating aniline with sodium nitrite and hydrochloric acid at $0^{\circ} C - 5^{\circ} C$ . This reaction is called diazotisation.
$N a N O_{2} + H Cl \to N a Cl + H N O_{2}$