Determine the solubility of Cr(OH)3 in mol L- 1 , if its Ksp is 2.7× 10- 31 M4 .

Question

Determine the solubility of Cr(OH)3 in mol L- 1 , if its Ksp is 2.7× 10- 31 M4 . (A) 1× 10- 8 (B) 8× 10- 8 (C) 1.1× 10- 8 (D) 0.18× 10- 8

Tardigrade Admin · Accepted Answer

The given compound will dissociate as <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/526b37991af213a9bd24da754909ae85-.png" /> Writing the expression for the solubility product, K sp =[ Cr 3+][ OH -]3= s ×(3 s )3=27 s 4 s =√[4]( K sp /27) s =√[4](2.7 × 10-31/27) s =1.0 × 10-8 mol L -1

Q. Determine the solubility of $C r (O H)_{3}$ in $m o l L^{- 1}$ , if its $K_{s p}$ is $2.7 \times 1 0^{- 31} M^{4}$ .

$1 \times 1 0^{- 8}$

$8 \times 1 0^{- 8}$

$1.1 \times 1 0^{- 8}$

$0.18 \times 1 0^{- 8}$

The given compound will dissociate as

Writing the expression for the solubility product,

$K_{s p} = [C r^{3 +}] [O H^{-}]^{3} = s \times (3 s)^{3} = 27 s^{4}$

$s = 4 \frac{K _{s p}}{27}$

$s = 4 \frac{2.7 \times 1 0 ^{- 31}}{27}$

$s = 1.0 \times 1 0^{- 8} m o l L^{- 1}$

Q. Determine the solubility of Cr(OH)3​ in molL−1 , if its Ksp​ is 2.7×10−31M4 .

1×10−8

8×10−8

1.1×10−8

0.18×10−8