d=1⋅25g/mL, conc, of solution =3M =3 moles in one litre of the solution.
Molar mass of NaCl=23+35⋅5=58⋅5gmol−1
Volume of solution =1L=1000mL
Mass of solution =d×V =1⋅25gmL−1×1000mL =1250g
Mass of solute (NaCl)=n× molar mass =3×58⋅5:175⋅5g
Mass of solvent
= Mass of solution − mass of solute =1250−175.5=1074.5g