Δ H for CaCO3(s) → CaO(s) + CO2(g) is 176 kJ mol-1 at 1240 K. The Δ E for the change is equal to

Question

Δ H for CaCO3(s) → CaO(s) + CO2(g) is 176 kJ mol-1 at 1240 K. The Δ E for the change is equal to (A) 160 kJ (B) 165.6 kJ (C) 186.3 kJ (D) 180.0 kJ

Tardigrade Admin · Accepted Answer

Δ H = Δ E + Δ nRT ∴ Δ E= 176 - 1 × 8.314 × 8.314 × 1240 × 10-3 = 165.6 kJ

Q. $Δ H$ for $C a C O_{3} (s) \to C a O (s) + C O_{2} (g)$ is $176 k J m o l^{- 1}$ at $1240 K$ . The $Δ E$ for the change is equal to