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Tardigrade
Question
Chemistry
Degree of dissociation of NH4OH in water is 1.8× 10-5, then hydrolysis constant of NH4Cl is:
Q. Degree of dissociation of
N
H
4
O
H
in water is
1.8
×
10
−
5
,
then hydrolysis constant of
N
H
4
Cl
is:
2470
166
Bihar CECE
Bihar CECE 2004
Equilibrium
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A
1.8
×
10
−
5
B
1.8
×
10
−
10
C
5.55
×
10
−
5
D
5.55
×
10
−
10
Solution:
K
h
=
K
b
K
w
where
K
w
=
ionic product of water
=
1
×
1
0
−
14
K
b
=
degree of dissociation of
N
H
4
O
H
=
1.8
×
1
0
−
5
K
h
=
1.8
×
1
0
−
5
1
×
1
0
−
14
=
0.555
×
1
0
−
9
=
5.55
×
1
0
−
10