Given set A={1,2,3,4} and relation, xRy if x divides y. ⇒ Relation ={(1,1),(2,2),(3,3),(4,4),(1,2),(1,3)(1,4),(2,4)} Reflexive We have, xRy⇔y/x for x,y∈A For any x∈A, we have x/x⇒xRx
Thus, xRx for all x∈A. So, R is reflexive on A. SymmetryR ia not symmetry because, if y/x, then x may not divide y. For example 4/2 but 2/4 Transitive, Let x,y,z∈A, such that xRy and yRz.
Then, xRy and yRz⇒xy and yz⇒xz.
So, R is a transitive relation on A.