Decreasing order of stability of ions is (i) CH3 - C+H - CH3 (ii) CH3-C+H-OCH3 (iii) CH3 - C+H - COCH3

Question

Decreasing order of stability of ions is (i) CH3 - C+H - CH3 (ii) CH3-C+H-OCH3 (iii) CH3 - C+H - COCH3 (A) (i) > (ii) > (iii) (B) (ii) > (i) > (iii) (C) (ii) > (iii) > (i) (D) (iii) > (i) > (ii)

Tardigrade Admin · Accepted Answer

The dispersal of the charge stabilizes the carbocation. More the number of electron donating groups are present, greater the dispersal of positive charge and therefore more the stability of carbocation can be observed.
So, the order is

C H_{3} - C + H - OC H_{3} > C H_{3} - C + H - C H_{3} > C H_{3} - C + H - COC H_{3}

Q. Decreasing order of stability of ions is (i) CH3​−C+H−CH3​ (ii) CH3​−C+H−OCH3​ (iii) CH3​−C+H−COCH3​

(i) > (ii) > (iii)

(ii) > (i) > (iii)

(ii) > (iii) > (i)

(iii) > (i) > (ii)

Q. Decreasing order of stability of ions is
(i) $C H_{3} - C^{+} H - C H_{3}$
(ii) $C H_{3} - C^{+} H - OC H_{3}$
(iii) $C H_{3} - C^{+} H - COC H_{3}$