Decreasing order of s-character is sp, sp2,sp3 -hybrid orbitals:

Question

Decreasing order of s-character is sp, sp2,sp3 -hybrid orbitals: (A)  sp3 > sp2 > sp  (B)  sp > sp2 > sp3 (C)  sp3 > sp > sp2 (D)  sp2 > sp > sp3

Tardigrade Admin · Accepted Answer

s-character in s p-hybrid orbital =50 % s-character in s p2 hybrid orbital =33 % s-character in s p3 hybrid orbital =25 % Decreasing order s p>s p2>s p3

Q. Decreasing order of $s$ -character is $s p, s p^{2}, s p^{3}$ -hybrid orbitals:

$s p^{3} > s p^{2} > s p$

$s p > s p^{2} > s p^{3}$

$s p^{3} > s p > s p^{2}$

$s p^{2} > s p > s p^{3}$

s-character in $s p$ -hybrid orbital $= 50% s$ -character in $s p^{2}$ hybrid orbital $= 33%$ s-character in $s p^{3}$ hybrid orbital $= 25%$ Decreasing order $s p > s p^{2} > s p^{3}$

Q. Decreasing order of s-character is sp,sp2,sp3 -hybrid orbitals:

sp3>sp2>sp

sp>sp2>sp3

sp3>sp>sp2

sp2>sp>sp3