Decomposition of X exhibits a rate constant of 0.05 μ g/year. How many years are required for the decomposition of 5 μg of X into 2.5 μ g ?

Question

Decomposition of X exhibits a rate constant of 0.05 μ g/year. How many years are required for the decomposition of 5 μg of X into 2.5 μ g ? (A) 50 (B) 25 (C) 20 (D) 40

Tardigrade Admin · Accepted Answer

Rate constant ( K )=0.05 μ g / year means zero order reaction t 1 / 2=( a 0/2 K )=(5 μ g /2 × 0.05 μ g / year )=50 year

Q. Decomposition of $X$ exhibits a rate constant of $0.05 μg / ye a r$ . How many years are required for the decomposition of 5 $μ$ g of $X$ into $2.5 μ g$ ?

50

25

20

40

Rate constant $(K) = 0.05 μg /$ year

means zero order reaction

$t_{1/2} = \frac{a _{0}}{2 K} = \frac{5 μg}{2 \times 0.05 μg / ye a r} = 50$ year

Q. Decomposition of X exhibits a rate constant of 0.05μg/year. How many years are required for the decomposition of 5 μg of X into 2.5μg ?

50

25

20

40

Rate constant (K)=0.05μg/ year means zero order reaction t1/2​=2Ka0​​=2×0.05μg/year5μg​=50 year

Q. Decomposition of $X$ exhibits a rate constant of $0.05 μg / ye a r$ . How many years are required for the decomposition of 5 $μ$ g of $X$ into $2.5 μ g$ ?

Rate constant $(K) = 0.05 μg /$ year

means zero order reaction

$t_{1/2} = \frac{a _{0}}{2 K} = \frac{5 μg}{2 \times 0.05 μg / ye a r} = 50$ year