de-Broglie wavelength of an electron accelerated by a voltage of 50 V is close to (|e| = 1.6× 10-19 C, me = 9.1×10-31 kg, h = 6.6×10-34 Js):

Question

de-Broglie wavelength of an electron accelerated by a voltage of 50 V is close to (|e| = 1.6× 10-19 C, me = 9.1×10-31 kg, h = 6.6×10-34 Js): (A) 0.5 mathringA (B) 1.2 mathringA (C) 1.7 mathringA (D) 2.4 mathringA

Tardigrade Admin · Accepted Answer

λ=(h/m v)=(h/√2 m q V) For electron m=9.1 × 10-31 kg ; q=1.6 × 10-19 C ; h=6.625 × 10-34 Js λ=√(150/V) mathringA=√(150/50) mathringA=1.7 mathringA

Q. de-Broglie wavelength of an electron accelerated by a voltage of $50 V$ is close to
$(∣ e ∣ = 1.6 \times 1 0^{- 19} C, m_{e} = 9.1 \times 1 0^{- 31} k g, h = 6.6 \times 1 0^{- 34} J s) :$

$0.5 \overset{˚}{A}$

$1.2 \overset{˚}{A}$

$1.7 \overset{˚}{A}$

$2.4 \overset{˚}{A}$

$λ = \frac{h}{m v} = \frac{h}{2 m q V}$
For electron
$m = 9.1 \times 1 0^{- 31} k g; q = 1.6 \times 1 0^{- 19} C;$
$h = 6.625 \times 1 0^{- 34} J s$
$λ = \frac{150}{V} \overset{˚}{A} = \frac{150}{50} \overset{˚}{A} = 1.7 \overset{˚}{A}$

Q. de-Broglie wavelength of an electron accelerated by a voltage of 50V is close to (∣e∣=1.6×10−19C,me​=9.1×10−31kg,h=6.6×10−34Js):

0.5A˚

1.2A˚

1.7A˚

2.4A˚