de-Broglie wavelength associated with a ball of mass 1 kg having kinetic energy 0.5 J is

Question

de-Broglie wavelength associated with a ball of mass 1 kg having kinetic energy 0.5 J is (A) 6.63 × 10-30 m (B) 6.63 × 10-34 m (C) 1.32 × 10-33 m (D) 1.32 × 10-34 m

Tardigrade Admin · Accepted Answer

de-Broglie wavelength, λ=(h/p)=(h/√2mK) Here, m = 1 kg, K = 0.5 J h = 6.63 Ã 10-34 J s, λ = ? λ=(6.63×10-34/√2×1×0.5)=6.63×10-34 m

Q. de-Broglie wavelength associated with a ball of mass 1 kg having kinetic energy 0.5 J is

6.63 × 10^-30 m

6.63 × 10^-34 m

1.32 × 10^-33 m

1.32 × 10^-34 m

de-Broglie wavelength, $λ = \frac{h}{p} = \frac{h}{2 m K}$
Here, m = 1 kg, K = 0.5 J
$h = 6.63 \times 1 0^{- 34} J s, λ = ?$
$λ = \frac{6.63 \times 1 0 ^{- 34}}{2 \times 1 \times 0.5} = 6.63 \times 1 0^{- 34} m$

Q. de-Broglie wavelength associated with a ball of mass 1 kg having kinetic energy 0.5 J is

6.63 × 10-30 m

6.63 × 10-34 m

1.32 × 10-33 m

1.32 × 10-34 m

de-Broglie wavelength, λ=ph​=2mK​h​ Here, m = 1 kg, K = 0.5 J h=6.63×10−34Js,λ=? λ=2×1×0.5​6.63×10−34​=6.63×10−34m

6.63 × 10^-30 m

6.63 × 10^-34 m

1.32 × 10^-33 m

1.32 × 10^-34 m

de-Broglie wavelength, $λ = \frac{h}{p} = \frac{h}{2 m K}$
Here, m = 1 kg, K = 0.5 J
$h = 6.63 \times 1 0^{- 34} J s, λ = ?$
$λ = \frac{6.63 \times 1 0 ^{- 34}}{2 \times 1 \times 0.5} = 6.63 \times 1 0^{- 34} m$