D (-)- Threose longrightarrow NaBH 4 longrightarrow ( R ) D (-)- Erythrose stackrel NaBH 4 longrightarrow ( P ) Which of the following statement is correct about P and R?

Question

D (-)- Threose longrightarrow NaBH 4 longrightarrow ( R ) D (-)- Erythrose stackrel NaBH 4 longrightarrow ( P ) Which of the following statement is correct about P and R? (A) Both are optically active (B) Both are optically inactive (C) P is optically inactive and R is optically active (D) Neither P nor R has asymmetric carbon

Tardigrade Admin · Accepted Answer

P is optically inactive as it contains the center of symmetry and R is optically active as it contains no element of symmetry.

Q. D(−)− Threose ⟶NaBH4​⟶(R) D(−)− Erythrose ⟶NaBH4​​(P) Which of the following statement is correct about P and R?

Both are optically active

Both are optically inactive

P is optically inactive and R is optically active

Neither P nor R has asymmetric carbon

P is optically inactive as it contains the center of symmetry and R is optically active as it contains no element of symmetry.

Q. $D (-) -$ Threose $⟶ N a B H_{4} ⟶ (R)$
$D (-) -$ Erythrose $⟶ N a B H_{4} (P)$
Which of the following statement is correct about P and R?