Question

Cyclotron is adjusted to give proton beam, magnetic induction is 0.15 $wb{m}^{-2}$ and the extreme radius is 1.5 m. The energy of emergent proton in MeV will be

• A. 34.2
• B. 3.42
• C. 2.43
• D. 24.3

Answer 1

Answer: (C)

$KE=\frac{B^2{q}^2{R}^2}{2m}$