Cyclic hydrocarbon ' A ' has all the carbon and hydrogen atoms in a single plane. All the carbon-carbon bonds have the same length, less than 1.54 mathringA , but more than 1.34 mathringA . The C - C - C bond angle will be

Question

Cyclic hydrocarbon ' A ' has all the carbon and hydrogen atoms in a single plane. All the carbon-carbon bonds have the same length, less than 1.54 mathringA , but more than 1.34 mathringA . The C - C - C bond angle will be (A) 109°28' (B) 100° (C) 180° (D) 120°

Tardigrade Admin · Accepted Answer

In aromatic system all the carbon and hydrogen atoms are present in one plane and all C - C bond lengths are same due to resonance and all carbon atoms have s p2 hybridisation, so the bond angle is 120°.

Q. Cyclic hydrocarbon ' $A$ ' has all the carbon and hydrogen atoms in a single plane. All the carbon-carbon bonds have the same length, less than $1.54 \overset{˚}{A}$ , but more than $1.34 \overset{˚}{A}$ . The $C - C - C$ bond angle will be

$10 9^{\circ} 2 8^{'}$

$10 0^{\circ}$

$18 0^{\circ}$

$12 0^{\circ}$

In aromatic system all the carbon and hydrogen atoms are present in one plane and all $C - C$ bond lengths are same due to resonance and all carbon atoms have $s p^{2}$ hybridisation, so the bond angle is $12 0^{\circ}$ .

Q. Cyclic hydrocarbon ' A ' has all the carbon and hydrogen atoms in a single plane. All the carbon-carbon bonds have the same length, less than 1.54A˚, but more than 1.34A˚. The C−C−C bond angle will be

109∘28′

100∘

180∘

120∘