CuSO4 decolourises on addition of KCN, the product is

Question

CuSO4 decolourises on addition of KCN, the product is (A) [Cu (CN)4]2- (B) Cu2+ gets reduced to form [Cu(CN)4]3- (C) Cu (CN)2 (D) CuCN

Tardigrade Admin · Accepted Answer

[CuSO4 + 2KCN arrow Cu(CN)2 + K2SO4] × 2 2Cu (CN)2 arrow Cu2(CN)2 + (CN)2 Cu2(CN)2 + 6KCN arrow 2K3Cu (CN)4 2CuSO4 + 10KCN arrow 2K3Cu(CN)4 + 2K2SO4 + (CN)2

Q. $C u S O_{4}$ decolourises on addition of $K CN$ , the product is

$[C u (CN)_{4}]^{2 -}$

$C u^{2 +}$ gets reduced to form $[C u (CN)_{4}]^{3 -}$

$C u (CN)_{2}$

$C u CN$

$[C u S O_{4} + 2 K CN \to C u (CN)_{2} + K_{2} S O_{4}] \times 2$
$2 C u (CN)_{2} \to C u_{2} (CN)_{2} + (CN)_{2}$
$C u_{2} (CN)_{2} + 6 K CN \to 2 K_{3} C u (CN)_{4}$
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$2 C u S O_{4} + 10 K CN \to 2 K_{3} C u (CN)_{4} + 2 K_{2} S O_{4} + (CN)_{2}$

Q. CuSO4​ decolourises on addition of KCN, the product is

[Cu(CN)4​]2−

Cu2+ gets reduced to form [Cu(CN)4​]3−

Cu(CN)2​

CuCN