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Tardigrade
Question
Physics
Current through 3 Ω resistor is 0.8 ampere, then potential drop through 4 Ω resistor is
Q. Current through
3
Ω
resistor is
0.8
ampere, then potential drop through
4
Ω
resistor is
5019
229
AIPMT
AIPMT 1993
Current Electricity
Report Error
A
9.6 V
11%
B
2.6 V
23%
C
4.8 V
54%
D
1.2 V
12%
Solution:
Current across
3
Ω
=
0.8
A
6
Ω
is in parallel, current across
6
Ω
=
0.4
A
Total current
=
1.2
A
∴
potential difference across
4
Ω
resistor
=
1.2
A
×
4
Ω
=
4.8
V
.