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  4. Current through 3 Ω resistor is 0.8 ampere, then potential drop through 4 Ω resistor is

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Q. Current through $3\, \Omega$ resistor is $0.8$ ampere, then potential drop through $4\, \Omega$ resistor isPhysics Question Image

AIPMTAIPMT 1993Current Electricity

Solution:

Current across $3\, \Omega = 0.8\, A $
$ 6\, \Omega $ is in parallel, current across $6\, \Omega = 0.4\, A $
Total current $= 1.2 \,A$
$\therefore $ potential difference across $4\, \Omega$ resistor $=1.2\, A \times 4\, \Omega $
$= 4.8\, V.$