Current measured by the ammeter (A) in the reported circuit when no current flows through 10 Ω resistance. will be A.

Question

Current measured by the ammeter (A) in the reported circuit when no current flows through 10 Ω resistance. will be A. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Using the condition of a balanced wheat stone bridge, ⇒ ( R /3)=(4/6) ⇒ R =2 Ω So the effective resistance of the circuit is R eq =(6 × 9/6+9)=(18/5) Ω i =(36/ R eq )=10 A

Q. Current measured by the ammeter $(A)$ in the reported circuit when no current flows through $10 Ω$ resistance. will be ______ $A$ .

Using the condition of a balanced wheat stone bridge,
$\Rightarrow \frac{R}{3} = \frac{4}{6} \Rightarrow R = 2 Ω$
So the effective resistance of the circuit is
$R_{e q} = \frac{6 \times 9}{6 + 9} = \frac{18}{5} Ω$
$i = \frac{36}{R _{e q}} = 10 A$

Q. Current measured by the ammeter (A) in the reported circuit when no current flows through 10Ω resistance. will be ______A.

Using the condition of a balanced wheat stone bridge, ⇒3R​=64​⇒R=2Ω So the effective resistance of the circuit is Req​=6+96×9​=518​Ω i=Req​36​=10A

Q. Current measured by the ammeter $(A)$ in the reported circuit when no current flows through $10 Ω$ resistance. will be ______ $A$ .

Using the condition of a balanced wheat stone bridge,
$\Rightarrow \frac{R}{3} = \frac{4}{6} \Rightarrow R = 2 Ω$
So the effective resistance of the circuit is
$R_{e q} = \frac{6 \times 9}{6 + 9} = \frac{18}{5} Ω$
$i = \frac{36}{R _{e q}} = 10 A$