Current I versus time t graph through a conductor is shown in the figure. Average current through the conductor in the interval 0 to 15 s is

Question

Current I versus time t graph through a conductor is shown in the figure. Average current through the conductor in the interval 0 to 15 s is (A) 1 A (B) 10 A (C) 7.5 A (D) 5 A

Tardigrade Admin · Accepted Answer

Δ q= Area (I / t) Δ q=(1/2) ⋅ 10 × 15=75 C i text avg =(75/15)=5 A

Q. Current $I$ versus time $t$ graph through a conductor is shown in the figure. Average current through the conductor in the interval $0$ to $15 s$ is

1 A

10 A

7.5 A

5 A

$Δ q =$ Area $(I / t)$
$Δ q = \frac{1}{2} \cdot 10 \times 15 = 75 C$
$i_{avg} = \frac{75}{15} = 5 A$

Q. Current I versus time t graph through a conductor is shown in the figure. Average current through the conductor in the interval 0 to 15s is

1 A

10 A

7.5 A

5 A

Δq= Area (I/t) Δq=21​⋅10×15=75C iavg ​=1575​=5A

Q. Current $I$ versus time $t$ graph through a conductor is shown in the figure. Average current through the conductor in the interval $0$ to $15 s$ is

$Δ q =$ Area $(I / t)$
$Δ q = \frac{1}{2} \cdot 10 \times 15 = 75 C$
$i_{avg} = \frac{75}{15} = 5 A$