Question

Current $I$ versus time $t$ graph through a conductor is shown in the figure. Average current through the conductor in the interval $0$ to $15\, s$ is

• A. 1 A
• B. 10 A
• C. 7.5 A
• D. 5 A

Answer 1

Answer: (A)

$\Delta q=$ Area $(I / t)$
$\Delta q=\frac{1}{2} \cdot 10 \times 15=75 C$
$i_{\text {avg }}=\frac{75}{15}=5 \,A$