Current i=2.5 A flows along the circular coil whose equation is given by x2+y2=9 (x and y are in cm ). If the magnetic field is given by π x × 10-9 T at point (0,0,4) cm, then find the value of x.

Question

Current i=2.5 A flows along the circular coil whose equation is given by x2+y2=9 (x and y are in cm ). If the magnetic field is given by π x × 10-9 T at point (0,0,4) cm, then find the value of x. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Magnetic field on the axis of circular loop, B=((μ0/4 π)) × (2 π I R2/(R2+z2)3 / 2) where, R= Radius of loop =3 × 10-2 m ⇒ B =10-7 × (2 π × 2.5 × 32 × 10-4/125 × 10-6) hatk =((9 π/25) × 10-5 T ) hatk=(36 π × 10-7 T ) hatk

Q. Current i=2.5A flows along the circular coil whose equation is given by x2+y2=9(x and y are in cm). If the magnetic field is given by πx×10−9T at point (0,0,4)cm, then find the value of x.

Magnetic field on the axis of circular loop, B=(4πμ0​​)×(R2+z2)3/22πIR2​ where, R= Radius of loop =3×10−2m ⇒B=10−7×125×10−62π×2.5×32×10−4​k^ =(259π​×10−5T)k^=(36π×10−7T)k^

Q. Current $i = 2.5 A$ flows along the circular coil whose equation is given by $x^{2} + y^{2} = 9 (x$ and $y$ are in $c m)$ . If the magnetic field is given by $π x \times 1 0^{- 9} T$ at point $(0, 0, 4) c m$ , then find the value of $x$ .