Cu ⊕+e- longrightarrow Cu , E ominus=x1 volt Cu 2++2 e- longrightarrow Cu , E ominus=x2 volt, then for Cu 2++e- longrightarrow Cu ⊕, E ominus (colt) will be

Question

Cu ⊕+e- longrightarrow Cu , E ominus=x1 volt Cu 2++2 e- longrightarrow Cu , E ominus=x2 volt, then for Cu 2++e- longrightarrow Cu ⊕, E ominus (colt) will be (A) x1-2 x2 (B) x1+2 x2 (C) x1-x2 (D) 2 x2-x1

Tardigrade Admin · Accepted Answer

Cu ⊕+e- longrightarrow Cu , E ominus 1=x1 V......(i) Cu 2++2 e- longrightarrow Cu , E ominus 2=x2 V.....(ii) Net equation Cu 2++e- longrightarrow Cu ⊕ E3= ? ...(iii) Is obtained by equations (ii) - (i) ∴ E3=(n2 E2-n1 E1/n3) =(2 × x1-1 × x1/1)=2 x2-x1

Q. $C u^{\oplus} + e^{-} ⟶ C u, E^{⊖} = x_{1}$ volt
$C u^{2 +} + 2 e^{-} ⟶ C u, E^{⊖} = x_{2}$ volt, then for
$C u^{2 +} + e^{-} ⟶ C u^{\oplus}, E^{⊖}$ (colt) will be

$x_{1} - 2 x_{2}$

$x_{1} + 2 x_{2}$

$x_{1} - x_{2}$

$2 x_{2} - x_{1}$

Q. Cu⊕+e−⟶Cu,E⊖=x1​ volt Cu2++2e−⟶Cu,E⊖=x2​ volt, then for Cu2++e−⟶Cu⊕,E⊖ (colt) will be

x1​−2x2​

x1​+2x2​

x1​−x2​

2x2​−x1​

Cu⊕+e−⟶Cu,E⊖1​=x1​V......(i) Cu2++2e−⟶Cu,E⊖2​=x2​V.....(ii) Net equation Cu2++e−⟶Cu⊕E3​= ? ...(iii) Is obtained by equations (ii) - (i) ∴E3​=n3​n2​E2​−n1​E1​​ =12×x1​−1×x1​​=2x2​−x1​

Q. $C u^{\oplus} + e^{-} ⟶ C u, E^{⊖} = x_{1}$ volt
$C u^{2 +} + 2 e^{-} ⟶ C u, E^{⊖} = x_{2}$ volt, then for
$C u^{2 +} + e^{-} ⟶ C u^{\oplus}, E^{⊖}$ (colt) will be

$x_{1} - 2 x_{2}$

$x_{1} + 2 x_{2}$

$x_{1} - x_{2}$

$2 x_{2} - x_{1}$