Cu2 + ions reacts with Fe2 + ion according to the following reaction Cu2 ++2Fe2 +leftharpoons Cu+2Fe3 + At equilibrium the concentration of Cu2 + ions is not changed by the addition of

Question

Cu2 + ions reacts with Fe2 + ion according to the following reaction Cu2 ++2Fe2 +leftharpoons Cu+2Fe3 + At equilibrium the concentration of Cu2 + ions is not changed by the addition of (A) Cu2 + (B) Fe2 + (C) Cu (D) Fe3 +

Tardigrade Admin · Accepted Answer

Cu2 ++2Fe2 +leftharpoons Cu+2Fe3 + For this reaction at equilibrium the concentration of Cu2 + ions is not changed by the addition of Cu as it is solid. So its molar concentration is always taken as unity.

Q. $C u^{2 +}$ ions reacts with $F e^{2 +}$ ion according to the following reaction

$C u^{2 +} + 2 F e^{2 +} ⇌ C u + 2 F e^{3 +}$

At equilibrium the concentration of $C u^{2 +}$ ions is not changed by the addition of

$C u^{2 +}$

$F e^{2 +}$

Cu

$F e^{3 +}$

$C u^{2 +} + 2 F e^{2 +} ⇌ C u + 2 F e^{3 +}$

For this reaction at equilibrium the concentration of $C u^{2 +}$ ions is not changed by the addition of Cu as it is solid. So its molar concentration is always taken as unity.

Q. Cu2+ ions reacts with Fe2+ ion according to the following reaction Cu2++2Fe2+⇌Cu+2Fe3+ At equilibrium the concentration of Cu2+ ions is not changed by the addition of

Cu2+

Fe2+

Cu

Fe3+

Cu2++2Fe2+⇌Cu+2Fe3+ For this reaction at equilibrium the concentration of Cu2+ ions is not changed by the addition of Cu as it is solid. So its molar concentration is always taken as unity.

Q. $C u^{2 +}$ ions reacts with $F e^{2 +}$ ion according to the following reaction

$C u^{2 +} + 2 F e^{2 +} ⇌ C u + 2 F e^{3 +}$

At equilibrium the concentration of $C u^{2 +}$ ions is not changed by the addition of

$C u^{2 +}$

$F e^{2 +}$

$F e^{3 +}$

$C u^{2 +} + 2 F e^{2 +} ⇌ C u + 2 F e^{3 +}$

For this reaction at equilibrium the concentration of $C u^{2 +}$ ions is not changed by the addition of Cu as it is solid. So its molar concentration is always taken as unity.