Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
CrO42 - (yellow) changes to Cr2O72 - (orange) in pH = x and vice-versa in pH = y. Hence, x and y are
Q.
C
r
O
4
2
−
(yellow) changes to
C
r
2
O
7
2
−
(orange) in pH = x and vice-versa in pH = y. Hence, x and y are
9523
196
NTA Abhyas
NTA Abhyas 2020
The d-and f-Block Elements
Report Error
A
6, 8
47%
B
6, 5
17%
C
8, 6
27%
D
7, 7
10%
Solution:
C
r
O
4
2
−
(yellow) changes to
C
r
2
O
7
2
−
(orange) in acidic medium so pH = x = 6.
2
C
r
O
4
2
−
+
2
H
+
→
C
r
2
O
7
2
−
+
H
2
O
The opposite reaction takes place in basic medium so pH = y = 8.
C
r
2
O
7
2
−
+
2
O
H
−
→
2
C
r
O
4
2
−
+
H
2
O